**The Demise of for Loops Jessica Hamrick**

however if you find the max number with the classic vay you can use loops. list = [3,8,2,9] current_max_number = list[0] for number in list: if number>current_max_number: current_max_number = number print current_max_number #it will display 9 as big number... Or, even better, if you could just operate over the arrays without any loops at all? Well, you can! In this post, Iâ€™m going to go through a few interesting examples of how using NumPy, list comprehensions, and for loops can be used for the same applications, and furthermore, how well these different approaches actually perform.

**The Demise of for Loops Jessica Hamrick**

it just randomizes the array so instead of shuffle and all that just pass in your list to tje bubble_sort function â€“ Joran Beasley Aug 15 '12 at 5:25 bubble_sort(data_list);print â€¦... This is pretty much impossible without at least one loop and at least one if condition (maybe two) inside the loop. Or maybe a ternatry operator instead of an if, but the difference seems immaterial.

**python find the maximum number in a list using a loop**

Is there a fast way to find the location of a maximal entry in a Numeric array? I realize I could do something along the lines of flattening it, finding the maximum value, and then searching for that value, but that means going over the array twice. I could also use argmax to find the position of the largest value in each column, make a new array with dimension one less containing those... How to calculate min/max values in a list without using the min()/max() functions? (self.learnpython) submitted 3 years ago by RetiredUnicorn. Hello there, I have an assignment which asks that I write a program that has the user input values and the program then adds the values to a list. the program is supposed to then output the number of scores, the minimum and maximum scores, the average

**Sort 3 Integers without using if condition or using only**

Find closest value for every element in array Sort 3 Integers without using if condition or using only max() function Given three inteÂgers, print them in sorted order withÂout using if condition.... Rather than making 4 passes to find the max and min elements and their respective indices, we can find the max element and its index in a single pass (taking advantage of enumerate and the fact that max takes a key function), and then simply searching the left side of that for the min element.

## How To Find Max In Array Python Without Using Loops

### In Python how can I write a loop that will print a value

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## How To Find Max In Array Python Without Using Loops

### The function np.argmax will determine which index in the array where the maximum value arises in the intensity363 array, this index value is then matched to the input wavelengths array to find the value of the input which produces this maximum value.

- This is pretty much impossible without at least one loop and at least one if condition (maybe two) inside the loop. Or maybe a ternatry operator instead of an if, but the difference seems immaterial.
- Is there a fast way to find the location of a maximal entry in a Numeric array? I realize I could do something along the lines of flattening it, finding the maximum value, and then searching for that value, but that means going over the array twice. I could also use argmax to find the position of the largest value in each column, make a new array with dimension one less containing those
- Find closest value for every element in array Sort 3 Integers without using if condition or using only max() function Given three inteÂgers, print them in sorted order withÂout using if condition.
- I realize I could do something along the lines of flattening it, finding the maximum value, and then searching for that value, but that means going over the array twice. I could also use argmax to find the position of the largest value in each column, make a new array with dimension one less containing those maximal values, and repeat, but I can't see how to make that new array without doing a

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